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A84 Dutch |
Dutch Defense: Rubinstein Variation |
Akiba Rubinstein vs Rudolf Spielmann, 1912 |
0-1, 42 moves |
1119753 (#564) |
[Event "San Sebastian"] [Site "10"] [Date "1912.??.??"] [EventDate "?"] [Round "?"] [Result "0-1"] [White "Akiba Rubinstein"] [Black "Rudolf Spielmann"] [ECO "A84"] [WhiteElo "?"] [BlackElo "?"] [PlyCount "84"] 1.d4 {Notes by Jacques Mieses and Dr. Savielly Tartakower.} e6 2.c4 f5 3.Nc3 Bb4 4.Bd2 Nf6 5.g3 O-O 6.Bg2 d6 7.a3 Bxc3 8.Bxc3 Nbd7 9.Qc2 c5 10.dxc5 Nxc5 11.Nf3 Nce4 12.O-O Bd7 13.Rfd1 {? Mieses: White should play 14.Rad1. As the game shows, the f2-pawn must be protected.} Rc8 14.Bxf6 Qxf6 15.Qb3 Rc7 16.Ne1 {?! Mieses: Better was 16.Nd4. *** Tartakower: If 16.Nd4, then, as in the text, 16...Nc5 17.Qb4 f4, etc. If 16.e3 e5.} Nc5 17.Qb4 f4 {!} 18.Nd3 {Tartakower: If 18.Rxd6 fxg3 19.fxg3 Qf2+ 20.Kh1 Qxe2 21.h3 (21.Rd2 Rf1+ followed by mate) 21...Ne4 and wins.} fxg3 19.fxg3 Nxd3 20.Rxd3 Qf2+ 21.Kh1 Bc6 {!} 22.e4 Rcf7 23.Re1 {Tartakower: If 23.Rxd6 Qe2 24.Qe1 (still parrying the triple threat ...Rf1+ or ...Bxe4 or ...Rf2) 24...Qxb2 25.Rxe6 Rf2, etc.} a5 {!} 24.Qc3 Qc5 25.b4 Bxe4 {! Mieses: Brilliant and correct!} 26.Rxe4 {Mieses: The queen cannot be captured because of mate in two moves. After 26.Bxe4 the following winning continuation for Black is shown: 26...Rf1+ 27.Rxf1 Rxf1+ 28.Kg2 Rg1+! 29.Kf3 Qh5+ 30.Ke3 Qxh2, etc. But, as pointed out in "Deutsche Schachblaetter", playing 26.Rf3! White has the opportunity for strong resistance with big drawing chances; for example: 26...Rxf3 27.Qxf3! Rxf3 28.bxc5, or 26....Qc6 27.b5! Rxf3 28.Qxf3 Bxf3 29.bxc6 Bxc6 30.Bxc6 bxc6 31.Rxe6, etc.} Rf1+ 27.Bxf1 Rxf1+ 28.Kg2 Qf2+ 29.Kh3 Rh1 30.Rf3 {! Tartakower: If 30.Rf4 Qxh2+ 31.Kg4 Qh5+ mate, and if 30.Rxe6 Qxh2+ 31.Kg4 Qh3+, followed by 32...Qxe6.} Qxh2+ 31.Kg4 Qh5+ 32.Kf4 Qh6+ 33.Kg4 g5 {! Tartakower: A splendid point, establishing a mating net at one stroke.} 34.Rxe6 {Tartakower: If 34.Rf8+ Kxf8 35.Kf3 axb4 36.axb4 Kf7 with 37...Qf6 to follow.} Qxe6+ 35.Rf5 h6 {Mieses: Enough to win, but here was also a quicker solution: 35...Qe4+ 36.Kxg5 h6+ 37.Kf6 (37.Kg6 Qe8+) 37...Re1! 38.Kg6 Qg4+.} 36.Qd3 Kg7 37.Kf3 Rf1+ {!} 38.Qxf1 Qxf5+ 39.Kg2 Qxf1+ 40.Kxf1 axb4 41.axb4 Kf6 42.Kf2 h5 0-1 |
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